package com.thealgorithms.datastructures.trees;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.LinkedList;
import java.util.Map;
import java.util.Queue;
/* The following class implements a vertical order traversal
in a tree from top to bottom and left to right, so for a tree :
1
/ \
2 3
/ \ \
4 5 6
\ / \
7 8 10
\
9
the sequence will be :
4 2 7 1 5 9 3 8 6 10
*/
public class VerticalOrderTraversal {
/*Function that receives a root Node and prints the tree
in Vertical Order.*/
public static ArrayList<Integer> verticalTraversal(BinaryTree.Node root) {
if (root == null) {
return new ArrayList<>();
}
/*Queue to store the Nodes.*/
Queue<BinaryTree.Node> queue = new LinkedList<>();
/*Queue to store the index of particular vertical
column of a tree , with root at 0, Nodes on left
with negative index and Nodes on right with positive
index. */
Queue<Integer> index = new LinkedList<>();
/*Map of Integer and ArrayList to store all the
elements in a particular index in a single arrayList
that will have a key equal to the index itself. */
Map<Integer, ArrayList<Integer>> map = new HashMap<>();
/* min and max stores leftmost and right most index to
later print the tree in vertical fashion.*/
int max = 0, min = 0;
queue.offer(root);
index.offer(0);
while (!queue.isEmpty()) {
if (queue.peek().left != null) {
/*Adding the left Node if it is not null
and its index by subtracting 1 from it's
parent's index*/
queue.offer(queue.peek().left);
index.offer(index.peek() - 1);
}
if (queue.peek().right != null) {
/*Adding the right Node if it is not null
and its index by adding 1 from it's
parent's index*/
queue.offer(queue.peek().right);
index.offer(index.peek() + 1);
}
/*If the map does not contains the index a new
ArrayList is created with the index as key.*/
if (!map.containsKey(index.peek())) {
ArrayList<Integer> a = new ArrayList<>();
map.put(index.peek(), a);
}
/*For a index, corresponding Node data is added
to the respective ArrayList present at that
index. */
map.get(index.peek()).add(queue.peek().data);
max = Math.max(max, index.peek());
min = Math.min(min, index.peek());
/*The Node and its index are removed
from their respective queues.*/
index.poll();
queue.poll();
}
/*Finally map data is printed here which has keys
from min to max. Each ArrayList represents a
vertical column that is added in ans ArrayList.*/
ArrayList<Integer> ans = new ArrayList<>();
for (int i = min; i <= max; i++) {
ans.addAll(map.get(i));
}
return ans;
}
}